(x^-4y^2/x^4y^-3)^-2

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Solution for (x^-4y^2/x^4y^-3)^-2 equation: 


D( x )

x^4 = 0

x = 0

((x^-4*y^2)/(x^4))*y^-3 = 0

x^4 = 0

x^4 = 0

1*x^4 = 0 // : 1

x^4 = 0

x = 0

x = 0

x = 0

((x^-4*y^2)/(x^4))*y^-3 = 0

((x^-4*y^2)/(x^4))*y^-3 = 0

x^-8*y^-1 = 0 // : y^-1

x^-8 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((x^-4*y^2)/(x^4))*y^-3)^-2 = 0

x^16*y^2 = 0 // : y^2

x^16 = 0

x = 0

x in { 0} 

x belongs to the empty set

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